Update: I have driven an additional 850 miles on regular and the mpg is remaining within a fraction of what I got on premium. However, many others have reported a drop in mpg when burning regular gas. I think I know why I am not seeing what others have reported.
If there are any engine techs out there, I would love to get your opinion regarding this theory.
Here's what I think is happening:
The atmospheric pressure at this altitude (7000 ft.) is usually around 11.34 psi as opposed to 14.7 psi at sea level. The compression ratio of this engine is 11.5:1. So, at sea level, the compression-stroke cylinder pressure in this engine would be approximately 169.05 psi (11.5 x 14.7). However, at this altitude, it would be approximately 130.41 psi (11.5 x 11.34).
The reason one would normally experience a degradation in engine performance/efficiency using regular gas in this engine is due to the ECU retarding the timing to prevent detonation. Detonation occurs when the fuel-air mixture in the cylinder explodes abruptly rather than producing a smooth burn. Higher octane fuel slows the burn rate to prevent detonation so the timing is not adjusted by the ECU. Detonation is a function of the pressure within the cylinder. At this elevation, the lower atmospheric pressure results in a lower compression-stroke cylinder pressure (130.41 psi) which is not sufficient to cause detonation using regular gas. Therefore the timing is not retarded by the ECU and the mpg is not effected. So, I believe I can burn regular and save money without suffering any penalty.....except the corresponding reduction in power the comes with the high elevation. I am driving a 340 HP sedan instead a 429 HP sedan....sigh.
What say you?
Thanks for any input.
Bill
First things first. Higher octane gases do not burn slower. It does require a higher combination of temperature and pressure before it self-ignites
Thank you.
I got the wrong idea about the burn rate from Wikipedia:
"Octane ratings are not indicators of the energy content of fuels. They are only a measure of the fuel's tendency to burn in a controlled manner, rather than exploding in an uncontrolled manner."
Best regards,
Bill
That's correct. The higher you go, the less octane you need, unless you run with boost.
Took a 460 mile one day trip over the weekend from MA to NJ and back (see other thread). Got 29.2 MPG round trip on 87.
427435 stated:
"I guess I'm missing your point."
Sorry, no offense intended. I just wanted to make sure this thread is accurate.
However, in your original post you stated: "Higher octane gases do not burn slower".
As my previous post explains, higher octane fuels do burn slower. The slower burn rate is how detonation is prevented. Iso-octane prevents detonation by controlling (slowing) the burn rate in order to yield smooth flame propagation across the combustion chamber and thereby preventing an uncontrolled spontaneous explosion (detonation).
And, please, I don't want this to turn into a contest. You win. OK?
Take care,
Bill
Greetings,
I drive a 2014 5.0 R-Spec. I did a little test to see if using regular would adversly affect MPG. I live in the Colorado Springs area so my driving has been in higher elevations (between 6000 and 7000 feet). I don't know if that makes a difference or not, I thought I should mention it though. And, due to the altitude, the octane ratings are lower here than they are at sea level. I checked the milage with each fill up the old fasioned way and didn't use the car's MPG readout. I ignored the first tank full when computing MPG after changing to allow the OBDII to adjust. I drove 1,117 on premium and averaged 21.55 MPG. Then I changed over to regular and drove 893 miles and averaged 21.80 MPG. The slight difference might have been due to variations in traffic conditions. But, as you can see, regular seems to yield about the same as premium.
Please fix your signature to reflect the crank HP of using lower grade fuel.In any event, I'm running my 5.0 on a steady diet of regular gas.
Please fix your signature to reflect the crank HP of using lower grade fuel.![]()